1.

a)\ Zn+2HCl->ZnCl_2+H_2

b)

n_{Zn}={6,5}/{65}=0,1(mol)

n_{HCl}={100.14,6\%}/{36,5}=0,4(mol)

0,1<{0,4}/2->HCl dư 0,4-0,1.2=0,2(mol)

n_{ZnCl_2}=n_{H_2}=n_{Zn}=0,1(mol)

->V_{H_2}=0,1.22,4=2,24(l)

c)

m_{dd\ spu}=6,5+100-0,1.2=106,3(g)

->C\%_{ZnCl_2}={0,1.136}/{106,3}.100\%\approx 12,79\%

       C\%_{HCl\ du}={0,2.36,5}/{106,3}.100\%\approx 6,87\%

2.

a)

CuO+H_2  $$\xrightarrow{t^o}$$   Cu+H_2O

Fe_2O_3+3H_2  $$\xrightarrow{t^o}$$   2Fe+3H_2O

Fe_3O_4+4H_2  $$\xrightarrow{t^o}$$   3Fe+4H_2O

b)

Theo PT: n_{H_2}=n_{H_2O}={14,4}/{18}=0,8(mol)

->V=0,8.22,4=17,92(l)

BTKL: m=47,2+0,8.2-0,8.18=34,4(g)