a)

n_{S}=(37,2)/(32)=1,1625(mol)

n_{O_2}=(6,4)/(32)=0,2(mol)

$$S+O_2\xrightarrow[]{t^o}SO_2$$

(1,1625)/(1)>(0,2)/(1)

=>S \text{dư}

$$\xrightarrow[]{TheoPTHH}$$n_{S(pư)}=n_{O_2}=0,2(mol)

=>n_{S(dư)}=1,1625-0,2=0,9625(mol)

=>m_{S(dư)}=0,9625.32=30,8(g)

b)

$$\xrightarrow[]{TheoPTHH}$$n_{SO_2}=n_{O_2}=0,2(mol)

=>m_{SO_2}=0,2.64=12,8(g)

 #Bear

a)

n_S={37,2}/{32}=1,1625(mol)

n_{O_2}={6,4}/{32}=0,2(mol)

S+O_2  $$\xrightarrow{t^o}$$  SO_2

Do 1,1625>0,2->S dư.

Theo PT: n_{S\ pu}=n_{O_2}=0,2(mol)

->n_{S\ du}=1,1625-0,2=0,9625(mol)

->m_{S\ du}=0,9625.32=30,8(g)

b)

Theo PT: n_{SO_2}=n_{O_2}=0,2(mol)

->m_{SO_2}=0,2.64=12,8(g)