$$I=\frac{\xi }{R+{{R}_{0}}}\to \frac{1}{I}=\frac{R+{{R}_{0}}}{\xi }$$
Dựa vào đồ thị:
+ Khi R = 80Ω
$$\to \frac{1}{I}=\frac{R+{{R}_{0}}}{\xi }=100$$ $$\to {{R}_{0}}+80=100\xi $$
+ Khi R = 40Ω
$$\to \frac{1}{I}=\frac{R+{{R}_{0}}}{\xi }=60$$ $$\to {{R}_{0}}+40=60\xi $$
$$\Rightarrow \xi =1,0V$$
=> D