a)

M+2HCl->MCl_2+H_2

MO+2HCl->MCl_2+H_2O

Đặt CT chung hh là A

->n_A=n_{ACl_2}

->{5,03}/A={9,52}/{A+71}

->A=79,53

->M<79,5

->63,5

->M=65(Zn)

Đặt n_{Zn}=x(mol);n_{ZnO}=y(mol)

->65x+81y=5,03;x+y=n_{ZnCl_2}={9,52}/{136}=0,07

->x=0,04;y=0,03

->n_{H_2}=x=0,04(mol)

->V=0,04.22,4=0,896(L)

b)

Zn+2H^{+}->Zn^{2+}+H_2

ZnO+2H^{+}->Zn^{2+}+H_2O

->n_{H^+}=2x+2y=0,14(mol)

pH=1->[H^+]=0,1M

->V_{dd\ a x i t}={0,14}/{0,1}=1,4(L)

a)

Bảo toàn M: n_M+n_{MO}=n_{MCl_2}

->{5,03}/{M_X}={9,52}/{M_X+71}

->M_X≈79,54

->M_M<79,54

->M_M<79,54

->63,54

TH1: M=64(Cu) loại do Cu không tan trong HCl.

TH2: M=65(Zn)

Đặt n_{Zn}=x(mol);n_{ZnO}=y(mol)

->65x+81y=5,03(1)

Bảo toàn Zn: x+y=n_{ZnCl_2}={9,52}/{136}=0,07(2)

(1)(2)->x=0,04;y=0,03 nhận.

Bảo toàn electron: n_{H_2}=n_{Zn}=x=0,04(mol)

->V=0,04.22,4=0,896(L)

b)

pH=1->[H^+]=0,1M

Zn+2H^{+}->Zn^{2+}+H_2

0,03->0,06(mol)

ZnO+2H^{+}->Zn^{2+}+H_2O

0,04->0,08(mol)

->V_{dd\ H^+}={0,14}/{0,1}=1,4(L)