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thithin1978
6/21/2023 2:30:16 PM
Cho 0,78 gam hỗn hợp gồm Mg và Al tan hoàn toàn trong dung dịch H2SO4 loãng thu được 0,896 lít khí H2 và dung dịch chứa m gam muối. Giá trị của m là
A. 3,62. B. 4,62. C. 3,27. D. 2,70.
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Câu Trả Lời:
cia.vnam
nSO42- (muối) = nH2 = 0,04
—> m muối = 0,78 + 0,04.96 = 4,62 gam
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