=> Chọn D
n_(H_2)=m/M=4/2=2(mol)
->V_(H_2)=n.22,4=2.24,79=49,58(l)
n_(N_2)=m/M=(2,8)/28=0,1(mol)
->V_{N_2}=n.24,79=0,1.24,79=2,479(l)
n_{O_2}=m/M={6,4}/{32}=0,2(mol)
->V_{O_2}=n.24,79=0,2.24,79=4,958(l)
n_{CO_2}=m/M={22}/{44}=0,5(mol)
->V_{CO_2}=n.24,79=0,5.24,79=12,395(l)