3 tấn =3000000kg
n_C={3000000.98\%}/{12}=245000(mol)
n_S={3000000.1,5\%}/{32}=1406,25(mol)
C+O_2 $$\xrightarrow{t^o}$$ CO_2
S+O_2 $$\xrightarrow{t^o}$$ SO_2
Theo PT:
n_{CO_2}=n_C=245000(mol)
n_{SO_2}=n_S=1406,25(mol)
->V_{CO_2}=245000.22,4=5488000(l)
V_{SO_2}=1406,25.22,4=31500(l)