1.
n_{CaO\ t t}={4,48}/{56}=0,08(mol)
CaCO_3 $$\xrightarrow{t^o}$$ CaO+CO_2
Theo PT: n_{CaCO_3\ t t}=n_{CaO\ t t}=0,08(mol)
->H={0,08.100}/{10}.100\%=80\%
2.
n_{H_2O_2\ l t}={50.34\%}/{34}=0,5(mol)
2H_2O_2 $$\xrightarrow{t^o}$$ 2H_2O+O_2
Theo PT: n_{O_2\ l t}=1/2n_{H_2O_2\ l t}=0,25(mol)
->V_{O_2\ t t}=0,25.80\%.24,79=4,958(L)